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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$This page uses Ground Floor to style the page, click here to see some code examples. You can opt-out of this style and make your own design by removing the "default.css" link in the HTML.
Given the quadratic equation , the roots are given by .