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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

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Given the quadratic equation a x 2 + b x + c = 0 , the roots are given by x = b ± b 2 4 a c 2 a .